Digit available number of times in given range

package com.rrvtechdiamond;

import java.util.Scanner;

class NumberOfDigits

{

public static void main (String[] args) throws java.lang.Exception

{

Scanner scanner=new Scanner(System.in);

                System.out.println("Enter up to which range you want: "); 

int numberRange=scanner.nextInt();

System.out.println("Enter which digit you want");

int digit=scanner.nextInt();

int count=0;/*count for counting number of digit available within                     given range*/

//for loop start with 0 up to given range

for(int i=0;i<numberRange;i++){

int innerCount=0;/*this count for given digit is available or                                           not if given digit is find more than one time we                                                will print that i value*/

int j=i;

while(j>0)

{

int temp=j%10;

if(temp==digit)

{

innerCount++;

count++;

}

j=j/10;

}

if(innerCount>0){

System.out.println(i);

}

}

System.out.println("You enter digit comes in "+count+" times");

}

}

OUTPUT:

Enter up to which range you want:

100

Enter which digit you want

8

8

18

28

38

48

58

68

78

80

81

82

83

84

85

86

87

88

89

98

You enter digit comes in 20 times